Example 1. In the adjoining figure, O is the centre of the circle with radius 5cm. AB || CD. AB = 8cm and CD = 6cm. Determine PQ.
Solution:- AP = PB = 4cm [ AB = 8cm ]
CQ = QD = 3cm [ CD = 6cm] [ from the centre to the chord bisect the chord ]
OA and OC are joined Pythagoras Theorem
OP2 = OA2 - AP2 = 52 = 42 = 9
OP = 3cm
OQ2 = OC2 - CQ2 = 52 - 32 = 16
OQ = 4cm
PQ = PO + OQ = 3 + 4 = 7cm
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