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Theorem 2

Theorem 1. There is one and only one circle passing through three non-collinear points.

Given:- A, B and C are three non-collinear points

To prove:- One and only one circle are drawn through the points A, B and C.

Construction:- AB and BC are joined PL and QM are drawn perpendicular bisectors respectively of AB and BC to intersect at O.
OA, OB and OC are joined.

Proof:- O lie on PL, the perpendicular bisector of AB

OA = OB ........................(i)

similarty OB = OC...........................(ii)

from (i) and (ii)

OA = OB = OC = r, say

A circle is drawn taking O as centre and r as radius to pass through A, B and C.

Let there be another centre O’ and another radius s, of circle through A, B and C. O’ must lie on PL and QM. As two lines can intersect at only one point. Hence O and O’ coincide.

OA = O' A = r = s

Hence there is unique circle passing through A, B and C.

 

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