Pythagoras Theorem. (B audhayan Theorem)
Theorem 8.3: - In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Given: - is a right angle of
To Prove:-
Construction:- is drawn
Proof:- In
Or, AB2 = AC X AD ---------------------(i)
Similarly
Or, BC2 = AC X CD ---------------------(ii)
Adding (i) and (ii) we get
AB2 + BC2 = AC X AD + AC X CD
= AC X (AD + CD)
= AC X AC
= AC2
Or, AC2 = AB2 + BC2
Theorem 8.4 (Converse of Pythagoras Theorem): - In a triangle, if the square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.
Given:- In
To prove:-
Construction:- A triangle PQR is constructed such that PQ = AB, QR = BC and
Proof:- In
Or, PR2 = AB2 +BC2--------------(i) [PQ = AB, QR = BC]
But AC2 = AB2 + BC2 ------------(ii) (given)
Or, PR = AC
Or,
Hence
Example 13. Determine whether the triangle having sides (2a – 1) cm, and (2a + 1) cm is a right angled triangle.
Sol:- Let AB = (2a - 1) cm,
AC = (2a + 1) cm
is a right angled triangle.
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